If it's not what You are looking for type in the equation solver your own equation and let us solve it.
7m^2-32m+16=0
a = 7; b = -32; c = +16;
Δ = b2-4ac
Δ = -322-4·7·16
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-24}{2*7}=\frac{8}{14} =4/7 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+24}{2*7}=\frac{56}{14} =4 $
| 48+4w=169 | | 8n=74.4 | | -10=h/4-12 | | 3(k+7)=21 | | 1+5x+6−2x=3x+5 | | (2x-1)+4=8 | | 4r-27=-7 | | 3v+39=18 | | -5m-2=-17 | | -3(6-2x)=3(5x+3) | | r+4/7=-1/4 | | 10(p-7)=0 | | 2y+22=38 | | 0=4t^2-20t-6.7 | | 0,05x+4,5=x | | j6+45=51 | | 55+35p=160 | | –3x+5+5x–1=0 | | 1/2(10x+15)-3=14x+1 | | 8x+5=5x+20 | | 7/4=14/n | | 2(x+4)=3(2x-8) | | 3r=183r+6 | | 2x-5+x-1=3x-10 | | a2+2a–35=0 | | 1/4(40x-8x)=19x+2-5× | | (3x-4)+20=24 | | 13x+10=14x | | 100.48=1/3*3.14r^2r+2 | | 6u=(3) | | -165.836=-10.9k | | 112m=650+88m |